3^2+(x/2)^2=x^2

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Solution for 3^2+(x/2)^2=x^2 equation: 



3^2+(x/2)^2=x^2

We move all terms to the left:

3^2+(x/2)^2-(x^2)=0

determiningTheFunctionDomain
-x^2+(x/2)^2+3^2=0

We add all the numbers together, and all the variables

-x^2+(+x/2)^2+3^2=0

We add all the numbers together, and all the variables

-1x^2+(+x/2)^2+9=0

We multiply all the terms by the denominator


-1x^2*2)^2+(+x+9*2)^2=0

We add all the numbers together, and all the variables

-1x^2*2)^2+(x+18)^2=0

We add all the numbers together, and all the variables

-1x^2*2)^2+(x=0

Wy multiply elements

-2x^3=0

We do not support expression: x^3

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